Question

Can anyone write me the steps of how to graph y=(x-9)^, please?

Answer 1

first step is to put the (x-9)^2 into a standard form which is y=x^2−18x+81 then choose two integers larger than the x-value of the vertex point.next choose two integers smaller than the x-value of the vertex point. lastly substitute these values in place of "x" in the equation and solve for "y".

Explanation:

x | y

7 | 4

8 | 1

9 | 0

10 | 1

11 | 4

4=(11-9)^2

1=(10-9)^2

0=(9-9)^2

1=(8-9)^2

4=(7-9)^2