Answer:
Pr(only one of them will pass the driving test) = 0.38
Explanation:
The probability that Ben will pass = 0.8
Let Pr = pribability
Pr(Ben pass) = 0.8
Pr(Ben fail) = 1 - Pr(Ben pass) = 1-0.8
Pr(Ben fail) = 0.2
The probability that Tom will pass = 0.7
Pr (Tom pass) = 0.7
Pr (Tom fail) = 1 - Pr (Tom pass) = 1-0.7
Pr (Tom fail) = 0.3
Pr(only one pass) = Pr(Ben pass and Tom fail) + Pr (Tom pass and Ben fail)
Pr(only one pass) = (0.8 × 0.3) + (0.7 × 0.2)
Pr(only one pass) = 0.24 + 0.14
Pr(only one pass) = 0.38