Question

Consider the following diagram that displays a map of a set of circular running tracks in a park connected by a sidewalk that goes from point a on the circle that represents the outer track to the center of all the circles, k

more in the photo please help!

Answer 1

Answer:

62.8 \: {m}^{2}62.8m

2

Explanation:

Radius of outer circle = 6 m

Width of the track = 2 m

So, radius of inner circle = 6 - 2 = 4 m

Area of the track = Area of outer circle - Area of inner circle

\begin{gathered} = \pi {6}^{2} - \pi {4}^{2} \\ \\ = \pi( {6}^{2} - {4}^{2} ) \\ \\ = 3.14 \times (36 - 16) \\ \\ = 3.14 \times 20 \\ \\ = 62.8 \: {m}^{2} \end{gathered}

=π6

2

−π4

2

=π(6

2

−4

2

)

=3.14×(36−16)

=3.14×20

=62.8m

2