Question

Help me, I need a step by step solution ASAP

Answer 1

a)

`x=-1\\x=-(3)/(4)`

b)

`x=(11)/(6)`

Explanation:

`Formula: x=\frac{-b\frac{+}{}√(b^2-4ac) }{2a}`

`a)-4x^2+7x-3=0`

a= -4

b= 7

c= -3

`x=\frac{-(7)\frac{+}{}√((7)^2-4(-4)(-3)) }{2(-4)}`

`x=\frac{-7\frac{+}{}√(49-48) }{-8}`

`x=\frac{-7\frac{+}{}√(1) }{-8}`

`x=\frac{7\frac{+}{}1 }{-8}`

------------------------------

`x=(7+1 )/(-8)=(8)/(-8)=-1`

or

`x=(7-1 )/(-8)=(6)/(-8)=-(3)/(4)`

------------------------------

`b)36x^2-132x+121=0`

a= 36

b= -132

c= 121

`x=\frac{-b\frac{+}{}√(b^2-4ac) }{2a}`

`x=\frac{-(-132)\frac{+}{}√((-132)^2-4(36)(121)) }{2(36)}`

`x=\frac{132\frac{+}{}√(17424-17424) }{72}`

`x=\frac{132\frac{+}{}√(0) }{72}`

`x=\frac{132\frac{+}{}0 }{72}`

------------------------------------------------

`x=(132)/(72)`

`x=(132/6)/(72/6)=(22)/(12)=(11)/(6)`