Question

What is the mass of 7.525 x10^24 particles of sulfur difluoride SF2?

Answer 1

Mass will be equal to 874.56 gram

Step-by-step explanation:

Molar mass of sulfur = 32 u

Molar mass of Florine = 19 u

Therefore molar mass of
`SF_2`
`=32+2* 19=70u`

So mass of
`6.023* 10^(23)` particle is 70 gram

Therefore mass of 1 particle

`=(70)/(6.023* 10^(23))=11.62* 10^(-23)g`

Therefore mass of
`7.525* 10^(24)` particle is

`7.525* 10^(24)* 11.62* 10^(-23)=874.56gram`