Register
Find the zeros of the function f(x)=8x^2 +32
152k views
4 votes
Find the zeros of the function f(x)=8x^2 +32

User Antonioh
by
7.5k points

1 Answer

4 votes

Answer: no solution

Explanation:


8x^(2) +32=0

Factor out 8


8(x^(2) +4)=0

no solution

Why?

Think about the graph,
x^(2) shifted up 4 has no zeros, even with a vertical stretch of 8.

User ATek
by
8.3k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.3m questions

12.1m answers

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to cover field
A dealer sells a certain type of chair and a table for $40. He also sells the same sort of table and a desk for $83 or a chair and a desk for $77. Find the price of a chair, table, and of a desk.
Link Copied!