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Find the zeros of the function f(x)=8x^2 +32
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4 votes
Find the zeros of the function f(x)=8x^2 +32

User Antonioh
by
4.6k points

1 Answer

4 votes

Answer: no solution

Explanation:


8x^(2) +32=0

Factor out 8


8(x^(2) +4)=0

no solution

Why?

Think about the graph,
x^(2) shifted up 4 has no zeros, even with a vertical stretch of 8.

User ATek
by
5.5k points
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