Answer:
Both Na+ ion and Neon atom have the same number of electrons in their electronic configuration (10 electrons). Due to the similar number of electrons contained in Na+ ion and the Neon atom, they show some similar characteristics in that they have both achieved electronic stability and are relatively resistant to oxidation or reduction.
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Step-by-step explanation:
Na+ ion is a sodium atom that has lost an electron. Normally, Sodium atom has 11 protons in its nucleus and 11 electrons in its electronic configuration. So, to form an ion with a stable octet where electronic stability is key, Sodium atom loses an electron and subsequently has 10 electrons in its electronic configuration just like Neon ( l10 electrons in its electronic configuration), which is naturally at that stable electronic configuration.
So, due to the similar number of electrons contained in Na+ ion and the Neon atom, they show some similar characteristics in that they have both achieved electronic stability and are relatively resistant to oxidation or reduction.
But, the extra proton in Sodium ion's nucleus (11 protons compared to Neon's 10), ensures that both structures are different and have different properties. Forming an ion with this extra charge enables sodium to form ionic compounds and be soluble in water unlike Neon which is known to be very non-reactive.
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