Convert the given mass of Zn to moles:
(14.0 g) (1/65.32 mol/g) ≈ 0.214 mol Zn
According to the balanced reaction, 1 mol H₂ gas is produced for every 1 mol Zn consumed in the reaction, so get the same number of moles of H₂.
Convert this amount of H₂ to a volume at STP:
(0.214 mol H₂) (22.4 L/mol) ≈ 4.80 L H₂