Question

. Radiation of a certain wavelength causes electrons with a maximum kinetic energy of 0.64 eV to be ejected from a metal whose work function is 2.60 eV. What will be the maximum kinetic energy with which this same radiation ejects electrons from another metal whose work function is 2.23 eV?

Answer 1

Step-by-step explanation:

Given that,

Maximum kinetic energy is 0.64eV

K.E_max = 0.64eV

Work function is 2.60 eV

W_o = 2.60 eV

So, we have two case, we need to find the maximum kinetic energy when the work function is 2.23 eV

W_o = 2.23 eV

Using the photoelectric effect equation, we can determine the energy of incident light.

Then,

hf = KEmax + W_o

hf = 0.64 eV + 2.60 eV

hf = 3.24 eV

Second case

Using the same photoelectric equation and making kinetic energy subject of the formulae, so we will plug the new work function (2.23eV) into the equation to find the maximum kinetic energy

Then,

KE_max = hf - Wo

K.E_max = 3.24 eV - 2.23 eV

K.E_max = 1.01 eV.