Question

How many moles of N₂O₅ are produced when 3.00g of O₂ react completely in the following equation? 2N₂ + 5O₂ → 2N₂O₅ A. 0.0375 B. 0.0750 C. 0.234 D. 0.469

Answer 1

Answer: A. 0.0375

Step-by-step explanation:

To calculate the moles :

`\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}`

`\text{Moles of} O_2=(3.00g)/(32g/mol)=0.094moles`

`2N_2+5O_2(g)\rightarrow 2N_2O_5`

According to stoichiometry :

As 5 moles of
`O_2` give = 2 moles of
`N_2O_5`

Thus 0.094 moles of
`O_2` give =
`(2)/(5)* 0.094=0.0375moles` of
`N_2O_5`

Thus 0.0375 moles of
`N_2O_5` will be produced when 3.00g of O₂ react completely