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Given a circle with center (2, -5) and a point on the circle of (3, -3). Write the equation of the circle.

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Answer:

(x - 2)^2 + (y + 5)^2 = 5

Explanation:

If the center is at (h, k) : (2, -5), then the general form of the equation of this circle is

(x - 2)^2 + (y + 5)^2 = r^2, and we must find r^2.

We know that (3, -3) is a point on the circle. Substitute 3 for x and -3 for y in the above equation to find r^2:

(3 - 2)^2 + (-3 + 5)^2 = r^2, or

1^2 + 2^2 = r^2

Then r^2 = 5, and the desired equation is

(x - 2)^2 + (y + 5)^2 = 5 or (√5)^2

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