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Write the solubility product expression for the decomposition of Ag2CO3

1 Answer

3 votes

Answer:


Ksp=[Ag^+]^2[(CO_3)^(-2)]

Step-by-step explanation:

Hello,

In this case, we should start by writing the equilibrium dissociation of silver carbonate as:


Ag_2CO_3(s)\rightleftharpoons 2Ag^+(aq)+(CO_3)^(-2)(aq)

In such a way, by means of the law of mass action for heterogeneous equilibrium (as silver carbonate is solid), we represent the solubility product expression as shown below:


Ksp=[Ag^+]^2[(CO_3)^(-2)]

Best regards.

User Isaac Hildebrandt
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