Question

5d + 2(2-d) = 3(1+d) + 1 Solve for d

Answer 1

infinite solutions

Explanation:

5d + 2(2-d) = 3(1+d) + 1

Distribute

5d + 4-2d = 3 +3d +1

Combine like terms

3d +4 = 3d+4

Subtract 3d from each side

3d-3d +4 = 3d-3d +4

4=4

Since this is always true

d has infinite solutions

Answer 2

infinite solutions

Explanation:

5d + 2(2-d) = 3(1+d) + 1

Distribute

5d + 4-2d = 3 +3d +1

Combine like terms

3d +4 = 3d+4

Subtract 3d from each side

3d-3d +4 = 3d-3d +4

4=4

Since this is always true

d has infinite solutions