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How Many moles of mgbr2 are in 5.0 grams of mgbr2

User Chaddeus
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1 Answer

3 votes

Answer:


X=0.027mol

Step-by-step explanation:

Hello,

In this case, we need to apply a mole mass relationship via the molar mass of the magnesium bromide (MgBr2). For it, we first compute its molar mass as shown below:


M=m_(Mg)+2*m_(Br)=24.305 g/mol+2*79.904 g/mol\\\\M=184.113g/mol

Hence, we can understand that 1 mole of magnesium bromide contains 184.113 grams of mangnesium bromide, for that reason, for 5 grams of magnesium bromide we have the following moles:


184.113g\rightarrow 1mol\\5.0g \rightarrow X\\\\X=(5.0g*1mol)/(184.113g) \\\\X=0.027mol

Best regards.

User Wantok
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