Answer:
![X=0.027mol](https://img.qammunity.org/2021/formulas/chemistry/college/7p56s7qv9ynp1443k8bfn2tpz5dv4wlne8.png)
Step-by-step explanation:
Hello,
In this case, we need to apply a mole mass relationship via the molar mass of the magnesium bromide (MgBr2). For it, we first compute its molar mass as shown below:
![M=m_(Mg)+2*m_(Br)=24.305 g/mol+2*79.904 g/mol\\\\M=184.113g/mol](https://img.qammunity.org/2021/formulas/chemistry/college/k8p67digop3tb71k5utihei9jgu0z8vwmg.png)
Hence, we can understand that 1 mole of magnesium bromide contains 184.113 grams of mangnesium bromide, for that reason, for 5 grams of magnesium bromide we have the following moles:
![184.113g\rightarrow 1mol\\5.0g \rightarrow X\\\\X=(5.0g*1mol)/(184.113g) \\\\X=0.027mol](https://img.qammunity.org/2021/formulas/chemistry/college/g3tj4lqimcseykyj76oj2kszc5b9c40szh.png)
Best regards.