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A bottling company fills bottles with a mean of 500 mL of liquia, with a

standard deviation of 2 mL. Quality control randomly samples 20

bottles at a time. Consider the mean volume of liquid in the sample

bottles. What is the standard deviation of the sampling distribution of

this sample mean?

1 Answer

3 votes

Answer:

The standard deviation of the sampling distribution of this sample mean is 0.447 ml.

Explanation:

We are given that a bottling company fills bottles with a mean of 500 ml of liquia, with a standard deviation of 2 ml. Quality control randomly samples 20 bottles at a time.

Let
\bar X = sample mean volume of liquid in bottles

The Sampling distribution of the sample mean also follows normal distribution;

As we know that ; Population mean =
\mu = 500 ml

Population Standard deviation =
\sigma = 2 ml

n = sample of bottles = 20

Now, the mean of sampling distribution is given by;

Sample Mean,
\bar X = Population mean = 500 ml

And, standard deviation of the sampling distribution of this sample mean is given by;

Standard deviation =
(\sigma)/(√(n) ) =
(2)/(√(20) ) = 0.447 ml

Hence, the standard deviation of the sampling distribution of this sample mean is 0.447 ml.

User Jisna
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