Answer:
C. Jared is not correct because the cone and the cylinder have the same base and height so the cone holds 4,712/3≈1,571 centimeters cubed of sand.
Explanation:
We have a cone and a cylinder with the same base and height.
We can express the volume of the cylinder as:

being r the radius and H the height.
The volume of the cone can be written as:

As they have the same base and height, we know that the volume of the cylinder is 3 times the volume of the cone.
If the volume of the cylinder is 4,712 cm^3, then the volume of the cone is:
