1 Answer

KeshavDulal · Answer 1 · 2021-01-14T17:29:10+0000

Answer:

pH

= 12.54

OH- concentration 28.84

Step-by-step explanation:

KOH dissociates into K+ and OH-. The ratio of K+ and OH- ion is 1:1

In any aqueous solution, the H3O+ and OH - must satisfy the following condition -

[ H_3O^+] [OH^-] = k_w

[ H_3O^+] = (k_w)/( [OH^-])

$[H_3O^+] = \frac{1 * 10^(-14)}{3.5 *10^(-2)[H_3O^+] = 2.857 * 10^(-13)$ M

pH =

$- log [ H_3O^+]\\- log [2.857 * 10^(-13)]$

pH

$= - [-12.54]\\= 12.54$

pOH
= 14 - pH

pOH

$= 14 - 12.54\\= 1.46$

OH concentration
= antilog 1.46

OH- concentration 28.84

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