Answer:
A) 0.303
The probability that a randomly selected student from the class has brown eyes , given they are male
![P((B)/(M) ) = 0.3030](https://img.qammunity.org/2021/formulas/mathematics/college/i0ie3zk68vqus3rv6li61m52j3tv9qyqdv.png)
Explanation:
Explanation:-
Given data
Brown Blue Hazel Green
Females 13 4 6 9
Males 10 2 9 12
Let 'B' be the event of brown eyes
Total number of males n(M) = 33
Let B/M be the event of randomly selected student from the class has brown eyes given they are male
The probability that a randomly selected student from the class has brown eyes , given they are male
![P((B)/(M) ) = (n(B))/(n(M))](https://img.qammunity.org/2021/formulas/mathematics/college/d16rcygkvg4rn8aseirq03nc9oa8zu2jv3.png)
From table the brown eyes from males = 10
![P((B)/(M) ) = (10)/(33)](https://img.qammunity.org/2021/formulas/mathematics/college/gld6xekcmukytzsdc2f27tj833y94cfvbd.png)
![P((B)/(M) ) = 0.3030](https://img.qammunity.org/2021/formulas/mathematics/college/i0ie3zk68vqus3rv6li61m52j3tv9qyqdv.png)
Final answer:-
The probability that a randomly selected student from the class has brown eyes , given they are male
![P((B)/(M) ) = 0.3030](https://img.qammunity.org/2021/formulas/mathematics/college/i0ie3zk68vqus3rv6li61m52j3tv9qyqdv.png)