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The following observations on degree of polymerization for paper specimens are used to estimate the true average degree polymerization The data has been given in an R vector called "data Copy and paste

asked Jun 5, 2021 197k views

The following observations on degree of polymerization for paper specimens are used to estimate the true average degree polymerization The data has been given in an R vector called "data Copy and paste this code in R to create a boxplot and calculate the summary statistics Use the output and summary statistics to answer the following questions. data-c(418, 421, 421, 423, 425, 426, 432, 435, 437, 439, 445, 446, 449, 452, 454, 461, 464) boxplot(data, horizontal TRUE) mean(data) sd(data)

(a) Construct a boxplot of the data 420 430 440 450 460 420 425 430 435 440 445 450 455 0 420 430 440 450 460 o 420 430 440 450 460 Comment on any interesting features.
i) There is one outlier
ii) The data is strongly skewed
iii) There are no outliers
iv) The data appears to be centered near 438
v) The data appears to be centered near 428
vi) There is little or no skew
(b) Is it plausible that the given sample observations were selected from a symmetric distribution?
a) Yes
b) No
(c) Calculate a 95% confidence interval for true average degree of polymerization. (Round your answers to two decimal places.) Tip: If you get one bound correct and the other incorrect this could mean that your method for calculation is incorrect. Recheck your calculations and your critical value Does the interval suggest that 437 is a plausible value for true average degree of polymerization? o Yes o No Does the interval suggest that 449 is a plausible value?
a) Yes
b) No
(d) Perform a hypothesis test to test the following hypotheses: ??: 1 # 449 The t test statistic is: The p-value is: (Round your answers to two decimal places.) o 0.001 < p-value < 0.002 o 0.002< p-value <0.01 o 0.01 p-value< 0.02 o 0.02 < p-value < 0.05 o 0.05 p-value 0.10 Does the hypothesis test suggest that 449 is a plausible value?
a) Yes
b) No