Question

Find the turning point of y=x^2+10x+12

Answer 1

vertex = (- 5, - 13 )

Explanation:

given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 )

then the x- coordinate of the turning point ( vertex) is

x = -
`(b)/(2a)`

y = x² + 10x + 12 ← is in standard form

with a = 1, b = 10 , then

x = -
`(10)/(2)` = - 5

substitute x = - 5 into the equation and evaluate for y

y = (- 5)² + 10(- 5) + 12 = 25 - 50 + 12 = - 13

turning point = (- 5, - 13 )