Question

Unheated

heated
The unheated gas in the above system has a volume of 20.0L
at a temperature of 25.0°C and a pressure of 1.00 atm. The
gas is heated to a temperature of 100.0 °C while the volume
remains constant. What is the pressure of the heated gas?
Ignore the block labeled "A".

Answer 1

Answer:1.25

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Using the Combined Gas Law, which is:

`(P_1V_1)/(T_1) =(P_2V_2)/(T_2)`

(With
`P_1,V_1,T_1` being initial pressure, volume and temperature; and

`P_2,V_2,T_2` being the new values)

We can move the units around in order to solve for
`P_2`, which would look like this:

`P_(2) =(P_1V_1T_2)/(V_2T_1)`

Then we convert the Celsius temperature to Kelvin:

`25` °
`C` =
`289`
`K`

`100` °
`C` =
`373`
`K`

And now, we plug in all of the values and solve, with volume remaining as a constant:

`P_(2) =((1.00 atm) (20.0 L) (373 K))/((20.0 L) (298 K))`
`=`

`1.25`
`atm` or
`127`
`kPa`