In binary, what would be the largest number 2^9 would allow?

Tal Aloni asked Jun 18, 2023

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Tal Aloni asked Jun 18, 2023

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9 votes

Answer:

511

Step-by-step explanation:

(2 ^ 9) - 1 = 511

We first have 2 ^ 9 which is 512, but we subtract 1 becuase while it can hold 512 values, it starts at 0.

Kristjan answered Jun 25, 2023

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