Question

How many liters of 2M HCl is needed to make 1 L of 0.05M HCI?​

Answer 1

0.025L of 2M HCl

Step-by-step explanation:

This is a dilution problem involving the equation

`M_1V_1 = M_2V_2`

Where M is molarity in grams/liter and V is volume in liters, and 1 and 2 represent initial and final states, respectively.

We know that:

`M_1` = 2, as 2M HCl is the starting substance

`M_2` = 0.05, as 0.05M HCl is the desired final substance

`V_2` = 1, as 1 L is the desired volume of the final substance

Now you can solve for
`V_1`.

`2V_1 = 0.05(1)\\V_1 = (0.05)/(2) \\V_1 = 0.025`

Therefore, 0.025L of 2M HCl is needed to make 1 L of 0.05M HCl