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Find cos theta if csc theta = square root 5

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Answer:

cos theta = adjacent/hypotenuse =
(2)/(√(5) )

Explanation:

csc theta = hypotenuse/opposite =
√(5) /1 (reciprocal identity)

1^2 + b^2 =
√(5)^2 (pythagorean theorem)

b^2 = 5-1

b = 2

cos theta = adjacent/hypotenuse = 2/
√(5) (quotient identity)

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