96.4k views
1 vote
A pizza parlor has a special on a three-topping pizza. How many different special pizzas can be ordered if the parlor has 8 toppings to choose from?

User IvanIvanov
by
5.6k points

2 Answers

3 votes

Answer:

We assume the three toppings must be different.

Explanation:

Cheese :

3

choices

Toppings :

8

choices for the first,

7

for the second and

6

for the third, a total of

8

×

7

×

6

=

336

, IF the order of toppings were important -- which it isn't. This number is called the number of permutations .

Three things can be ordered in 6 ways (try this), so in the 336 permutations, there are groups of 6 that amount to the same combination :

123=132=213=231=312=321, etc.

So we have to divide the number of permutations by the number of orders to reach the number of combinations:

There are thus 336 : 6 = 56 possibilities for the toppings.

Since we need cheese AND toppings we multiply:

Number of different pizzas: 3 x 56 = 168.

Calculator : if you have the nCr function the answer would be:

3 x 8 nCr 3 = 168

Explanation:

User Andrey Sobolev
by
6.8k points
3 votes
I think the answer is 24
User BanikPyco
by
6.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.