86.7k views
2 votes
What is the vertex of the graph of f(x)=x^2+2x-15

User Vranvs
by
5.1k points

1 Answer

4 votes
f
(
x
)
=
x
2

2
x

15
f
(
x
)
=
x
2
-
2
x
-
15
Find the properties of the given parabola.
Tap for more steps...
Direction: Opens Up
Vertex:
(
1
,

16
)
(
1
,
-
16
)
Focus:
(
1
,

63
4
)
(
1
,
-
63
4
)
Axis of Symmetry:
x
=
1
x
=
1
Directrix:
y
=

65
4
y
=
-
65
4
Select a few
x
x
values, and plug them into the equation to find the corresponding
y
y
values. The
x
x
values should be selected around the vertex.
Tap for more steps...
x
y

1

12
0

15
1

16
2

15
3

12
x y -1 -12 0 -15 1 -16 2 -15 3 -12
Graph the parabola using its properties and the selected points.
Direction: Opens Up
Vertex:
(
1
,

16
)
(
1
,
-
16
)
Focus:
(
1
,

63
4
)
(
1
,
-
63
4
)
Axis of Symmetry:
x
=
1
x
=
1
Directrix:
y
=

65
4
y
=
-
65
4
x
y

1

12
0

15
1

16
2

15
3

12
x y -1 -12 0 -15 1 -16 2 -15 3 -12
image of graph
User Mordred
by
4.9k points