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How many moles are equal to 83.4 L of O2?

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Answer:


3.72mol

Step-by-step explanation:

Hello,

In this case, we consider that at STP conditions (273 K and 1 atm) we know that the volume of 1 mole of a gas is 22.4 L, thereby, for 83.4 L, the resulting moles are:


22.4L\rightarrow 1mol\\83.4L\rightarrow X\\X=(83.4L*1mol)/(22.4L)=3.72mol

This is a case in which we apply the Avogadro's law which relates the volume and the moles as a directly proportional relationship.

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User Ilian Iliev
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