Question

36. (Higher) 2Mg + O2 → 2Mgo. Limiting reactant is Mg (4 mol). What is the amount of

product (in mol)? PLEASE HELP ME HOW TO WORK THESE OUT!!

Answer 1

4 mol MgO

Step-by-step explanation:

convert the limiting reactant to product by using dimensional analysis in order to see how many moles total can be created of the product

4 mol Mg x
`(2 mol MgO)/(2 mol Mg)` = 4 mol MgO