One root of the equation "x^(2) -m^(2)x -m + 1 = 0" (with unknown x) is the number "x1 = 1". Determine the other root "x2".

Question

One root of the equation "
`x^(2) -m^(2)x -m + 1 = 0`" (with unknown x) is the number "x1 = 1". Determine the other root "x2".

Answer 1

The answer is 0; 3. Hope this helps

Answer 2

0; 3.

Explanation:

1) if to substitute x=1 into the given equation, it is possible to calculate the value of 'm':

1-m²-m+1=0; ⇔ m²+m-2=0; ⇒ m₁=-2; m₂=1;

2) if m=-2 and m=1, then the initial equation is:

x²-4x+3=0 or x²-x=0;

3) according to the item 3), the 2d root is:

x₂=3 or x₂=0.