Question

2 √3 / √7 - 3 rationalise

Answer 1

`\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}`

the question asks us to rationalise the given expression ! thus , we'll just have to remove the √7 from the denominator by any means.

well , let's start ~

`(2 √(3) )/( √(7 ) - 3) \\ \\ \implies \: (2 √(3) )/( √(7) - 3) \: * \: ( √(7) + 3)/( √(7) + 3) = \frac{2 √(21) + 6 √(3) }{( √(7) ) {}^(2) - (3) {}^(2) } \\ \\ \implies \: (2 √(21) + 6 √(3) )/(7 - 9) \\ \\ \implies \: (2 √(21) + 6 √(3) )/(2) \\ \\ \implies \: \frac{\cancel{2}( √(21) + 3 √(3)) }{\cancel{2} } \\ \\\bold\red{ \implies \: √(21 ) + 3 √(3)}`

hope helpful :D