Answer:
11
Explanation:
If two chords intersect in a circle, the product of the lengths of the segments of one chord equal the product of the segments of the other.
AC *CB = CD CE
4 * (10-4) = CD * 8
4 * 6 = 8 *CD
24 = 8 CD
Divide each side by 8
24/8 = CD
3 = CD
We want the length DE
DE = CD + CE
= 3 + 8
DE = 11