Answer:
a) the result capacitor
ct=c1+c2+c3+c4
ct=2×10^-6+4×10^-6+6×10^-6+8×10^-6
ct=20×10^-14
b)q=ct×v
q=20×10^-14×50
q=1000×10^-14 c
Step-by-step explanation:
c)v1=q/ct
v1=1000×10^-14/20×10^-14
v1=50 volt
v2=
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