Answer:
2.84g
Step-by-step explanation:
Step 1:
The balanced equation for the reaction. This is given below:
2SO2 + O2 —> 2SO3
Step 2:
Determination of the mass of O2 that reacted and the mass of SO3 produced from the balanced equation.
This is illustrated below:
Molar mass of O2 = 16x2 = 32g/mol
Mass of O2 from the balanced equation = 1 x 32 = 32g
Molar mass of SO3 = 32 + (16x3) = 80g/mol
Mass of SO3 from the balanced equation = 2 x 80 = 160g
Summary:
From the balanced equation above,
32g of O2 reacted to produce 160g of SO3.
Step 3:
Determination of the mass of O2 needed to produce 14.2g of SO3.
This can be achieved as shown below:
From the balanced equation above,
32g of O2 reacted to produce 160g of SO3.
Therefore, Xg of O2 will react to produce 14.2g of SO3 i.e
Xg of O2 = (32 x 14.2)/160
Xg of O2 = 2.84g
Therefore, 2.84g of O2 is needed to produce 14.2g of SO3.