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What is the pH of a solution formed when 100 ML of an acid with a pH of two is diluted 1 L with pure water

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Answer: look down hope I helped

Step-by-step explanation:

1) First convert to pOH as OH is the dissociating species in a base equilibrium.pH + pOH = 14 (at 25 C)pH=13, hence pOH = 1,Hence [OH] = 10^-1 Mdiluting by factor of 10 with pure water gives [OH] = 10^-2 MThe new pOH = 2, hence the new pH is 12In general, dilution (with pure water) by a factor of 10 moves the pH 1 unit in the direction of the pH of water (pH 7). i.e. it moves up for acids, down for bases.(At infinite dilution of either acids or bases, you’d have pure water - obvious when you think of it like that)

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