Ed is parallel to ab..can someone help me with the proof towards this?

asked Jun 18, 2021 74.9k views

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5 votes

Answer:

Area_ACD = [AC*CD*sinC]/2

Area_BCE = [BC*CE*sinC]/2

AC*CD = BC*CE (as Thales theorem AC/CE = BC/CD)

Then, Area_ACD = Area_BCE

PRS answered Jun 24, 2021

by PRS

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