183k views
5 votes
58.0 g of K2SO4 was dissolved in 500 g of water. What is the molality of this solution?

1 Answer

5 votes

Answer: The molality of solution is 0.66 mole/kg

Step-by-step explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.


Molarity=(n* 1000)/(W_s)

where,

n = moles of solute


W_s = weight of solvent in g

moles of
K_2SO_4 =
\frac{\text {given mass}}{\text {Molar Mass}}=(58.0g)/(174g/mol)=0.33mol

Now put all the given values in the formula of molality, we get


Molality=(0.33* 1000)/(500g)=0.66mole/kg

Therefore, the molality of solution is 0.66 mole/kg

User Mobilecat
by
7.5k points