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Ok! Water is added to 200. ml of a 2.0 M solution of CaCI2 to increase the volume of the solution to 450. ml. So what is the new concentration?
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Ok! Water is added to 200. ml of a 2.0 M solution of CaCI2 to increase the volume of the solution to 450. ml. So what is the new concentration?

User Jiayi
by
6.2k points

1 Answer

4 votes

Answer:

0.89M

Step-by-step explanation:

Because moles of solute do not change, we can write

M1V1 = M2V2

M - molarity, V - volume of solution

2.0M*200mL = M2*450mL

M2 = 0.89 M

User Szilard Muzsi
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6.4k points
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