Question

If 36.2g of Acetic Acid (HC2H302) was dissolved in 300. mL of water, what is the

molarity or concentration of the solution? (1000mL = 1L) Answer should be three
significant figures *
Your answer​

Answer 1

2.01 M

Step-by-step explanation:

Step 1: Calculate the moles of acetic acid (HC₂H₃O₂)

The molar mass of acetic acid is 60.05 g/mol. We will use this data to calculate the moles corresponding to 36.2 g of acetic acid.

`36.2g * (1mol)/(60.05g) = 0.603mol`

Step 2: Convert the volume of solution to liters

We will use the relation 1000 mL = 1 L. We assume that the volume of solution is that of water (300 mL)

`300mL * (1L)/(1000mL) = 0.300L`

Step 3: Calculate the molarity of the solution

The molarity is equal to the moles of solute (acetic acid) divided by the liters of solution

`M = (0.603mol)/(0.300L) = 2.01 M`