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A 12kg ball is given an initial velocity of 20m/s and then is rolled along the floor. A friction force of 5N opposes its motion. For what length of time will it roll before stopp…
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A 12kg ball is given an initial velocity of 20m/s and then is rolled along the floor. A friction force of 5N opposes its motion. For what length of time will it roll before stopp…
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Dec 14, 2021
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A 12kg ball is given an initial velocity of 20m/s and then is rolled along the floor. A friction force of 5N opposes its motion. For what length of time will it roll before stopping. Thanks in advance!
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Ibrahim Hussein
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a=F/m
=5/12
=0.42 m/s^2
Since the ball stops, it decelerates at a rate of 0.42 m/s^2 before stopping and it’s final velocity is 0 m/s.
t=(u-v)/a
=(20-0)/0.42
=48 s
Palvinder
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Dec 21, 2021
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Palvinder
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