Question

How many grams of C3H8 would be needed to produce 6.39 grams of CO2?

Answer 1

2.13g

Step-by-step explanation:

Atomic mass of CO2 = 12 + 32 = 44g/Mol

Atomic mass of C3H8 = 36 + 8 = 44g/Mol

Reaction

C3H8 + 5O2 --> 3CO2 + 4H2O

3CO2 = 6.39g

Required C3H8 = (6.39/(44 x 3)) x 44 = 2.13g