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Calculate the useful output energy of an electric motor which is 70% efficient if it uses 600 J of electrical energy.

User Lauren Quantrell
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1 Answer

11 votes
11 votes

Answer:

420J

Step-by-step explanation:

The formula (useful output ÷ total output) × 100 is used. We need to find the the useful output. So:

(useful ÷ 600) × 100 = 70(%)

We rearrange the formula so that 'useful' is the subject of the equation.

useful ÷ 600 = 0.7 {70 ÷ 100}

useful = 0.7 × 600

useful = 420J

User Sean Hunter
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