How many milliliters of a 0.215 molar solution are required to contain 0.0867 mol of NaBr

asked Nov 14, 2021 178k views

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7 votes

Answer: 403ml

Step-by-step explanation:

M=(mol)/(L)

Solve for L;

$L=(mol)/(M)\\L=(0.0867mol)/(0.215M)\\ L=0.403L$

Convert to mililiters

0.403L((1000ml)/(1L))=403ml

FishingIsLife answered Nov 17, 2021

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