Question

Consider the following reaction where Kc = 55.6 at 698 K.

H2(g) + I2(g) 2HI(g)

A reaction mixture was found to contain 2.29×10-2 moles of H2(g), 3.80×10-2 moles of I2(g) and 0.254 moles of HI(g), in a 1.00 liter container.

Is the reaction at equilibrium?
If not, what direction must it run in order to reach equilibrium?

The reaction quotient, Qc, equals
.

The reactionfill in the blank 2

A. must run in the forward direction to reach equilibrium.
B. must run in the reverse direction to reach equilibrium.
C. is at equilibrium.

Answer 1

B

No the reaction is not at equilibrium

The reaction must run to the left (reactants) to reach equilibrium

Qc = 74.14

Step-by-step explanation:

Qc = (0.254)^2 / ((2.29 x 10-2)(3.8 x 10-2))

Qc = 74.14

74.14 > 55.6

Qc > Kc