Answer:
Explanation:
Normally, in a problem like this one, you'd be given a couple of x-values at which to evaluate the function. Since you didn't do that here, I'll just invent a few: {-1, 0, 7, 11}.
For x = -1: substitute -1 for x in f(x) = x^2 -3x+2: f(-1) = (-1)^2 - 3(-1) + 2 = 6:
f(-1) = 6
Next:
f(0) = 0 - 0 + 2 = 2, so f(0) = 2
For x = 7, substitute 7 for x in f(x) = x^2 -3x+2: f(7) = 49 - 21 + 2 = 30 = f(7)
For x = 11, f(11) = 121 - 33 + 2 = 90 = f(11)