Question

Find the equation of the line with slope = -6 and passing through (-2,10). Write your equation in the

form y = mx + b.
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Answer 1

`(\stackrel{x_1}{-2}~,~\stackrel{y_1}{10})\qquad \qquad \stackrel{slope}{m}\implies -6 \\\\\\ \begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{-6}(x-\stackrel{x_1}{(-2)}) \\\\\\ y-10=-6(x+2)\implies y-10=-6x-12\implies y=-6x-2`