Question

our friend is constructing a balancing display for an art project. She has one rock on the left (ms=2.25 kgms=2.25 kg) and three on the right (total mass mp=10.1 kgmp=10.1 kg). The distance from the fulcrum to the center of the pile of rocks is rp=0.360 m.rp=0.360 m. Answer the two questions below, using three significant digits. Part A: What is the value of the torque (????pτp) produced by the pile of rocks? (Enter a positive value.)

Answer 1

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The torque produced by the pile of rocks is
`\tau = 35.63\ N \cdot m`

b

The distance of the single for equilibrium to occur is
`r_s =1.62 \ m`

Step-by-step explanation:

From the question we are told that

The mass of the left rock is
`m_s = 2.25 \ kg`

The mass of the rock on the right
`m_p = 10.1 kg`

The distance from fulcrum to the center of the pile of rocks is
`r_p = 0.360 \ m`

Generally the torque produced by the pile of rock is mathematically represented as

`\tau = m_p * g * r_p`

Substituting values

`\tau = 10.1 * 9.8 * 0.360`

`\tau = 35.63\ N \cdot m`

Generally we can mathematically evaluated the distance of the the single rock that would put the system in equilibrium as follows

The torque due to the single rock is

`\tau = m_s * g * r_s`

At equilibrium the both torque are equal

`35.63 = m_s * r_s * g`

Making
`r_s` the subject of the formula

`r_s = (35.63 )/(m_s * g)`

Substituting values

`r_s = (35.63 )/(2.25 * 9.8)`

`r_s =1.62 \ m`