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Need help with this chemistry problem

Need help with this chemistry problem-example-1
User Gadi A
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1 Answer

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Answer:

40g/mol

Step-by-step explanation:

Step 1:

Data obtained from the question. This includes the following:

Volume (V) = 500mL = 500/1000 = 0.5L

Mass of gass = 1g

Temperature (T) = – 23°C = – 23°C + 273 = 250K

Pressure (P) = 105 KPa = 105/101.325 = 1.04 atm

Number of mole (n) =?

Gas constant (R) = 0.082atm.L/Kmol

Step 2:

Determination of the number of mole of the gas.

With the ideal gas equation, the number of mole of the gas can be obtained as follow:

PV = nRT

Divide both side by RT

n = PV / RT

n = (1.04 x 0.5)/(0.082 x 250)

n = 0.025mole

Step 3:

Determination of the molar mass of the gas:

This is illustrated below:

Mass of the gas = 1g

Number of mole of the gas = 0.025mole

Molar Mass of the gas =..?

Number of mole = Mass /Molar Mass

Molar Mass = Mass /number of mole

Molar Mass of the gas = 1/0.025

Molar Mass of the gas = 40g/mol

Therefore, the molar mass of the gas is 40g/mol

User Quantumass
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