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If sin Θ = 2 over 3 and tan Θ < 0 , what is the value of cos Θ?

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\sin \theta = \frac 2 3


\tan \theta < 0

Positive sine, negative tangent, means we have a negative cosine. We're talking about the second quadrant.


\cos^2 \theta + \sin ^2 \theta = 1


\cos^2 \theta = 1 - \sin ^2\theta


\cos \theta = \pm √(1 - \sin ^2\theta)

We know it's negative,


\cos \theta = - √(1 - (2/3)^2) =-√(5/9) = - \frac 1 3 √(5)

Answer: -(1/3)√5

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