Answer:
Option C.
Explanation:
Number of purple markers = 2
Number of black marker = 1
Number of red markers = 3
Number of yellow markers = 2
Number of blue markers = 2
Total number of markers = 10
Probability to select randomly a red marker =

=

Now we keep with us and randomly select a marker again.
So remaining markers with us = (10 - 1) = 9
Probability of the randomly selected marker to be yellow P(yellow)
=

=

Probability of both the events (selecting red AND yellow) = P(red) × P(yellow)
=

=

=

Therefore,Option (C) will be the answer.