Question

Solve the logarithmic equation for x.

2 log x = log 2 + log(3x - 4)
x= [
(smaller value)
X
=
(larger value)

Answer 1

x = 2 or x = 4

Explanation:

Solve: 2 log x = log 2 + log(3x - 4)

log (x^2) = log 2 + log (3x - 4)

log (x^2) = log [2*(3x - 4)]

x^2 = 2*(3x - 4)

x^2 = 6x - 8

x^2 - 6x + 8 = 0

factor:

(x - 2 )(x - 4) = 0

x = 2 or x = 4